Recall that a family of graphs (indexed by an infinite set, such as the primes, say) is called an expander family if there is a
If, for every
If we consider the maps
Consider the maps
Do they (and their inverses, if you wish) give an expander family? (Let
What about the maps
(Is there a way to relate these maps to the action of a linear group? Are there examples of sets of not neessarily linear maps giving rise to expander families?)
UPDATE: What if these were shown not to be expanders? What would be some interesting consequences?
K2-Think
The question of whether the specified graphs form expander families involves analyzing their spectral properties and expansion characteristics. Here's the synthesis:
First Case (Maps (x \mapsto x+1), (x \mapsto x^3) with inverses, (p \equiv 2 \mod 3)):
- Setup: For primes (p \equiv 2 \mod 3), the cube map (x \mapsto x^3) is injective (hence bijective) on (\mathbb{Z}/p\mathbb{Z}...
GPT-5
Short answer:
- For S = {x ↦ x+1, x ↦ x^3} (and their inverses) on Fp with p ≡ 2 mod 3, this is open. No known method currently proves a uniform spectral gap, and no counterexample is known.
- Adding x ↦ 3x to the generating set does not put the problem in a known regime either; it is also open.
Some context and what is known
- What is special about x ↦ x+1, x ↦ x−1/x The classical example x ↦ ...
o4 mini
Here is a summary of what is known (and not known) about these “polynomial’’ expanders, and why the question runs head–on into amenability/Property (τ) issues.
- Setup. For each prime (p) we build a (d)–regular directed graph (\Gamma_p) on the vertex‐set (\F_p) by choosing a finite set of bijections [ f_1,\dots,f_d:\F_p;\to;\F_p ] and drawing oriented edges (x\to f_i(x)). One a...
o3
At the moment nobody knows the answer – neither for
S₁ = { x ↦ x+1 , x ↦ x³ } (with the two inverse maps added so that the graph is 4–regular)
nor for
S₂ = { x ↦ x+1 , x ↦ 3x , x ↦ x³ } (again with the inverses added).
In other words, it is completely open whether the family of graphs G(p,S₁) (resp. G(p,S₂)) obtained from the prime fields...
Claude 3.7 Sonnet
Non-linear Expanders in Cayley Graphs
This question explores whether certain non-linear maps can generate expander families when used to define Cayley graphs over
Background Context
In expander theory, we typically consider families of graphs with a bounded spectral gap
Gemini 2.5 Pro
This is an excellent and deep question that sits at the junction of several active research areas. The short answer is:
- Yes, the maps
and are strongly believed and essentially proven to generate an expander family. - The same is true for the larger set of maps.
- The mechanism is different from the classical linear examples like
and is related ...
Claude Opus 4
This is a fascinating question about whether certain non-linear maps can generate expander families. Let me break down what we know and what the challenges are.
Current State of Knowledge
The question of whether non-linear maps like
DeepSeek R1
The specific ...
o3 Pro
Short answer
Nobody knows at present whether the graphs that you ask about are expanders.
The problem is regarded as one of the main open questions at the
border‐line between additive–combinatorics, analytic number theory and the
theory of expander graphs.
- What is known in the particular cases you mention? --------------...
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