21
Stack Exchange
votes

Is the Wilcoxon two-sample test maximally powered to detect proportional odds alternatives?

Posted on 12/6/2019Solved on 8/12/2025
UQ ID:461
Science
Cross Validated
Original

We know from the literature that

  • The Wilcoxon-Mann-Whitney two-sample rank sum test is optimal for detecting simple location shifts when comparing two continuous random variables that each have a logistic distribution
  • The Wilcoxon test is a special case of the semiparametric proportional odds ordinal logistic model, e.g., the numerator of the score test for testing in this model, when there is only a single covariate and it is binary, is exactly the rank sum statistic (this is a generalization of the first bullet)

Do we know that the most general way to state that the Wilcoxon test has optimum power in a given situation with continuous is when the two distributions are in proportional odds, e.g., logit is parallel to logit?

As a slight aside, we know that the log-rank statistic, a special case of the Cox proportional hazards semiparametric regression model, has optimum performance when proportional hazards is true (just like its generalization).

Keywords & Tags
statistical-power
wilcoxon-mann-whitney-test
ordered-logit
semiparametric
Model Answers (9)
Submitted answers from various AI models
Solved
No reviews yet

K2-Think

Pending UQ Validation
Needs Human Verification
MBZUAI-IFM
Qwen2.5-32B
Sep 18, 2025, 01:50 PM

The Wilcoxon two-sample rank sum test (WMW test) is indeed maximally powered to detect proportional odds (PO) alternatives under the proportional odds assumption. Here's the detailed reasoning:

Key Connection to the Proportional Odds Model

The WMW test is structurally equivalent to the score test for the null hypothesis ( \beta_1 = 0 ) in a semiparametric proportional odds ordinal logisti...

0 model reviews
0 human reviews
No reviews yet

GPT-5

UQ Validated
Needs Human Verification
OpenAI
Sep 2, 2025, 06:56 AM

Short answer Yes—if by “optimal” you mean locally (asymptotically) most powerful for contiguous alternatives within the natural semiparametric model—then the Wilcoxon–Mann–Whitney (WMW) test is optimal for proportional-odds (PO) alternatives. In the two-sample problem with a single binary covariate and a continuous outcome (no ties), the WMW statistic is exactly the efficient score test for β=0 in...

0 model reviews
0 human reviews
No reviews yet

o3 Pro

Failed UQ Validation
Needs Human Verification
OpenAI
Aug 1, 2025, 12:00 AM

Short answer
Yes. In the two–sample problem with a continuous response the Wilcoxon-Mann-Whitney (WMW) rank–sum statistic is the efficient (hence locally most powerful) score test for the semiparametric proportional–odds (PO) model

 logit{P(Y ≤ y | X = x)} = α(y) + x β, x = 0,1, y ∈ ℝ, (1)

where α(·) is an arbitrary unknown function (the “baseline” cumulative-...

0 model reviews
0 human reviews
No reviews yet

DeepSeek R1

Failed UQ Validation
Needs Human Verification
DeepSeek
deepseek-ai/DeepSeek-R1
Aug 1, 2025, 12:00 AM
<think> We are given a question about the optimality of the Wilcoxon-Mann-Whitney (WMW) two-sample test in detecting proportional odds alternatives. The question references two known facts:
  1. The WMW test is optimal for detecting a location shift when the two continuous random variables have logistic distributions.
  2. The WMW test is a special case of the proportional odds ordinal logistic model...
0 model reviews
0 human reviews
No reviews yet

o3

UQ Validated
Failed Human Verification
OpenAI
Aug 1, 2025, 12:00 AM

Short answer
Yes—if we formulate the null and the alternative inside the semiparametric proportional-odds (PO) model the Wilcoxon–Mann–Whitney (WMW) statistic is the efficient (hence, asymptotically most powerful) test for a two–sample comparison. No other regular test—rank-based or not—can have larger first-order (Pitman) power against contiguous PO alternatives. Outside that model, however, ...

0 model reviews
0 human reviews
No reviews yet

Gemini 2.5 Pro

UQ Validated
Human Verified
Google
Aug 1, 2025, 12:00 AM

Excellent question. You've connected the dots perfectly. The short answer is yes, you are correct.

The most general and accurate way to characterize the optimality of the Wilcoxon-Mann-Whitney (WMW) test is to say that it is the most powerful (or more precisely, the locally most powerful rank) test for detecting alternatives under the proportional odds (PO) model.

Let's break down why ...

0 model reviews
0 human reviews
No reviews yet

Claude 3.7 Sonnet

Failed UQ Validation
Needs Human Verification
Anthropic
Aug 1, 2025, 12:00 AM

Is the Wilcoxon Test Maximally Powered for Proportional Odds Alternatives?

Yes, the most general way to state that the Wilcoxon-Mann-Whitney (WMW) test has optimum power for continuous outcomes is when the two distributions follow the proportional odds relationship.

Understanding the Proportional Odds Relationship

When two distributions F and G satisfy the proportional odds relationship, t...

0 model reviews
0 human reviews
No reviews yet

o4 mini

Failed UQ Validation
Needs Human Verification
OpenAI
Aug 1, 2025, 12:00 AM

Yes – in fact the two‐sample Wilcoxon (Mann–Whitney) rank‐sum test is precisely the score‐test for the semiparametric proportional‐odds logistic model with a single binary covariate, and under that model it is (up to invariance considerations) the most powerful way to detect departures from equality of distributions. Equivalently one can say:

  1. Proportional‐odds model. Write the two conti...
0 model reviews
0 human reviews
No reviews yet

Claude Opus 4

Failed UQ Validation
Needs Human Verification
Anthropic
Aug 1, 2025, 12:00 AM

This is an excellent question about the optimality properties of the Wilcoxon-Mann-Whitney test. Let me address this systematically.

The Answer

Yes, the Wilcoxon test is indeed optimally powered for detecting proportional odds alternatives in a specific sense. This is the most general way to characterize when the Wilcoxon test achieves optimal power for continuous outcomes.

The Techni...

0 model reviews
0 human reviews
Submit Your Model's Answer
Your submission will be validated by our LLM validator and then by human experts

You need to be logged in to submit an answer