Conditional expectation continuous in the conditioning argument?
Conditional expectation continuous in the conditioning argument?
Let
Given any point
Obviously, the continuity part is the non-trivial one. By Lusin's theorem, any measurable function (such as any version of the conditional expectation function) is "nearly continuous", but this is not quite enough for me.
Ideally the sufficient conditions for the above statement would not involve restrictions on the densities or conditional densities of
K2-Think
To determine sufficient conditions for the existence of a version ( f(X) ) of the conditional expectation ( E(Y \mid X) ) that is continuous at a given ( x_0 \in \mathcal{X} ), we focus on the behavior of the conditional distribution of ( Y ) given ( X = x ) as ( x ) approaches ( x_0 ), along with integrability properties of ( Y ).
Key Sufficient Conditions:
- **Integrability...
GPT-5
Short answer: In general, without some regularity of the conditional law of Y given X around x0, your claim is false. With a mild continuity of the regular conditional distribution at x0 and a local uniform integrability assumption, it is true. A very common and easy-to-check sufficient scenario is the “additive noise” model X=A+B with B independent of (A,Y) and having a bounded, continuous, stric...
o3 Pro
We use the notation
μ = law (X ,Y), μX = law (X), κ(x, ·) = μ( Y∈· | X = x)
for a regular conditional distribution.
Throughout, X takes its values in the Euclidean space 𝒳 ⊂ℝp endowed with the
usual topology and Y is integrable, i.e. EY < ∞.
- What can go wrong ---------------------------------------------------...
o4 mini
Here is a fairly general “kernel‐continuity + uniform‐integrability” condition which guarantees that one can choose a version of
f(x) ≔ E[Y | X=x]
that is continuous at a prescribed point x₀. In particular it does not force you to write down any explicit Lebesgue densities—only that the conditional distributions vary nicely in x.
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- The we...
DeepSeek R1
The problem is non-trivial because conditional expectations are only defined up to null sets, and we require continuity at a...
Gemini 2.5 Pro
Here is a detailed answer to your question, structured to first provide the general theoretical conditions and then apply them to your specific problem.
Summary of the Main Result
The core of your question is about the continuity of a function
Claude 3.7 Sonnet
Conditional Expectation Continuity: Sufficient Conditions
This is an interesting question about the continuity of conditional expectations. I'll present several sufficient conditions that should address your needs.
General Case
For the general setting with random vectors
**The co...
o3
Throughout let
(Ω ,𝔽 ,P) be a probability space,
X : Ω→ℝᵖ , Y : Ω→ℝ , E|Y|<∞.
Write P_X for the law of X.
A regular conditional distribution (r.c.d.) of Y given X will be denoted by μ_x , i.e.
P(Y∈B , X∈A)=∫_A μ_x(B) P_X(dx) for all Borel A⊂ℝᵖ , B⊂ℝ. (1)
Such a family (μ_x)_x always exists and is P_X–a.s. unique.
Goal
Given a point x₀∈ℝᵖ find conditions which guarantee that ...
Claude Opus 4
This is an interesting question about the regularity of conditional expectations. Let me provide some sufficient conditions and insights.
General Sufficient Conditions
Theorem 1 (Regular Conditional Distributions): If
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