11
Stack Exchange
votes

Conditional expectation continuous in the conditioning argument?

Posted on 8/18/2016
UQ ID:363
Science
Mathematics
Original

Let and be random vectors defined on a common probability space. takes values in a finite-dimensional space , while takes values in . The conditional expectation is then a random variable that is uniquely defined up to null sets. I am seeking a set of sufficient conditions on the joint distribution of for the following statement to be true:

Given any point , there exists a function such that (i) is a version of , and (ii) is continuous at .

Obviously, the continuity part is the non-trivial one. By Lusin's theorem, any measurable function (such as any version of the conditional expectation function) is "nearly continuous", but this is not quite enough for me. Ideally the sufficient conditions for the above statement would not involve restrictions on the densities or conditional densities of and . The problem that motivates this question has a complicated geometry, so it is difficult to characterize densities with respect to fixed dominating measures. If you require more structure to the problem (but ideally the question would be answered in more generality), you may assume: for a continuous function , , and the random vectors and are independent. However, and may concentrate on different subspaces of , each of which is a complicated manifold. Thank you in advance for your time!

Keywords & Tags
probability-theory
measure-theory
continuity
conditional-expectation
Model Answers (9)
Submitted answers from various AI models
Unsolved
No reviews yet

K2-Think

Pending UQ Validation
Needs Human Verification
MBZUAI-IFM
Qwen2.5-32B
Sep 18, 2025, 01:50 PM

To determine sufficient conditions for the existence of a version ( f(X) ) of the conditional expectation ( E(Y \mid X) ) that is continuous at a given ( x_0 \in \mathcal{X} ), we focus on the behavior of the conditional distribution of ( Y ) given ( X = x ) as ( x ) approaches ( x_0 ), along with integrability properties of ( Y ).

Key Sufficient Conditions:

  1. **Integrability...
0 model reviews
0 human reviews
No reviews yet

GPT-5

Failed UQ Validation
Needs Human Verification
OpenAI
Sep 2, 2025, 06:56 AM

Short answer: In general, without some regularity of the conditional law of Y given X around x0, your claim is false. With a mild continuity of the regular conditional distribution at x0 and a local uniform integrability assumption, it is true. A very common and easy-to-check sufficient scenario is the “additive noise” model X=A+B with B independent of (A,Y) and having a bounded, continuous, stric...

0 model reviews
0 human reviews
No reviews yet

o3 Pro

Failed UQ Validation
Needs Human Verification
OpenAI
Aug 1, 2025, 12:00 AM

We use the notation

  μ = law (X ,Y),   μX = law (X),   κ(x, ·) = μ( Y∈· | X = x)

for a regular conditional distribution.
Throughout, X takes its values in the Euclidean space 𝒳 ⊂ℝp endowed with the usual topology and Y is integrable, i.e. EY < ∞.


  1. What can go wrong ---------------------------------------------------...
0 model reviews
0 human reviews
No reviews yet

o4 mini

Failed UQ Validation
Needs Human Verification
OpenAI
Aug 1, 2025, 12:00 AM

Here is a fairly general “kernel‐continuity + uniform‐integrability” condition which guarantees that one can choose a version of

  f(x) ≔ E[Y | X=x]

that is continuous at a prescribed point x₀. In particular it does not force you to write down any explicit Lebesgue densities—only that the conditional distributions vary nicely in x.

––––––––––––––––––––––––––––––––––––––––

  1. The we...
0 model reviews
0 human reviews
No reviews yet

DeepSeek R1

UQ Validated
Needs Human Verification
DeepSeek
deepseek-ai/DeepSeek-R1
Aug 1, 2025, 12:00 AM
<think> We are given two random vectors: X taking values in a finite-dimensional space X ⊂ R^p, and Y taking values in R. We are to find sufficient conditions such that for any x0 in X, there exists a version f of the conditional expectation E(Y|X) that is continuous at x0.

The problem is non-trivial because conditional expectations are only defined up to null sets, and we require continuity at a...

0 model reviews
0 human reviews
No reviews yet

Gemini 2.5 Pro

Failed UQ Validation
Needs Human Verification
Google
Aug 1, 2025, 12:00 AM

Here is a detailed answer to your question, structured to first provide the general theoretical conditions and then apply them to your specific problem.

Summary of the Main Result

The core of your question is about the continuity of a function that represents the conditional expectation . A standard and powerful result in probability theory gives sufficient conditions for th...

0 model reviews
0 human reviews
No reviews yet

Claude 3.7 Sonnet

Failed UQ Validation
Needs Human Verification
Anthropic
Aug 1, 2025, 12:00 AM

Conditional Expectation Continuity: Sufficient Conditions

This is an interesting question about the continuity of conditional expectations. I'll present several sufficient conditions that should address your needs.

General Case

For the general setting with random vectors and , a sufficient condition for the existence of a version of that is continuous at is:

**The co...

0 model reviews
0 human reviews
No reviews yet

o3

Failed UQ Validation
Needs Human Verification
OpenAI
Aug 1, 2025, 12:00 AM

Throughout let
(Ω ,𝔽 ,P) be a probability space,  
X : Ω→ℝᵖ , Y : Ω→ℝ ,   E|Y|<∞.
Write P_X for the law of X.
A regular conditional distribution (r.c.d.) of Y given X will be denoted by μ_x , i.e.

  P(Y∈B , X∈A)=∫_A μ_x(B) P_X(dx) for all Borel A⊂ℝᵖ , B⊂ℝ. (1)

Such a family (μ_x)_x always exists and is P_X–a.s. unique.

Goal
Given a point x₀∈ℝᵖ find conditions which guarantee that ...

0 model reviews
0 human reviews
No reviews yet

Claude Opus 4

Failed UQ Validation
Needs Human Verification
Anthropic
Aug 1, 2025, 12:00 AM

This is an interesting question about the regularity of conditional expectations. Let me provide some sufficient conditions and insights.

General Sufficient Conditions

Theorem 1 (Regular Conditional Distributions): If admits a regular conditional distribution, then for every where the marginal density/distribution of has positive mass in every neighborhood, there exists ...

0 model reviews
0 human reviews
Submit Your Model's Answer
Your submission will be validated by our LLM validator and then by human experts

You need to be logged in to submit an answer