A holomorphic function sending integers (and only integers) to
A holomorphic function sending integers (and only integers) to
Does there exist a function
K2-Think
To determine if there exists a holomorphic function ( f ) on ( \mathbb{C} ) such that ( f(\mathbb{Z}) = {0,1,2,3} ) and ( f(z) \in {0,1,2,3} \implies z \in \mathbb{Z} ), we can draw inspiration from the known solution for the set ( {0,1,2} ).
Key Insight:
The function ( g(z) = 1 - \cos\left(\frac{\pi z}{2}\right) ) works for ( {0,1,2} ) because:
- It is entire (holomorp...
GPT-5
Yes. One can construct such an entire function. Below is a concrete (but not “closed-form elementary”) construction that uses standard approximation/interpolation tools from complex analysis and a simple Rouché-argument to control level sets.
Outline of the construction
- We want an entire f with
- f(n) ∈ {0,1,2,3} for every integer n (indeed we will force f(n) = n mod 4),
- and, conversely, ...
o3 Pro
Yes, such an entire function exists, although it cannot be written with a short “elementary’’ formula.
One can obtain it by a completely explicit (but admittedly rather long) construction that uses nothing deeper than
• the Weierstrass product theorem (to produce entire functions with prescribed zeros), and
• an elementary inductive perturbation argument (to make sure that the four values 0,1...
DeepSeek R1
- For every integer n, f(n) ∈ {0,1,2,3}.
- If f(z) is in {0,1,2,3} for some complex number z, then z must be an integer.
Additionally, note that we have a known example for the set {0,1,2}: g(z) = 1 - cos(πz/2). This function i...
Gemini 2.5 Pro
An excellent and deep question that connects several areas of complex analysis. The short answer is no, such a function does not exist.
Here is a step-by-step explanation of why this is the case.
1. Initial Analysis and Key Properties
Let f be the hypothetical function.
fis entire: Holomorphic on all of. fis not a polynomial: A non-constant polynomia...
o3
Yes – such an entire function exists.
We cannot write it in a short closed form (one cannot expect that: the
conditions single out a function with infinitely many prescribed zeros
and with four different “exceptional’’ values), but we can construct it
explicitly by standard approximation theorems. One may even choose the
function to be a (very large-degree) polynomial.
Below is a complete con...
Claude Opus 4
This is a fascinating question about constructing a holomorphic function with very specific properties. Let me analyze this problem systematically.
Analysis of the Problem
We need a holomorphic function
(the image of integers is exactly ) (only integers map to ${0,1,2...
o4 mini
Here is a short “no-go’’ proof. Assume, to the contrary, that there existed an entire non-constant
(f\colon\C\to\C) with
(1) (f(n)\in{0,1,2,3}) for every integer (n),
(2) (f(z)\in{0,1,2,3}\implies z\in\Z).
Define the monic quartic
[
P(w);=;w,(w-1),(w-2),(w-3);=;w^4-6w^3+11w^2-6w,.
]
Then by (1)–(2) the entire function
[
F(z);=;\frac{P\bigl(f(z)\bigr)}{\si...
Claude 3.7 Sonnet
A Holomorphic Function Mapping Integers (and Only Integers) to {0,1,2,3}
This is an interesting question about constructing a holomorphic function with specific value restrictions.
Understanding the Problem
We need to find a holomorphic function
maps integers to the set - If
for any $z \in \mathbb{...
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