Can Erdős-Turán theorem be generalised that way?
Can Erdős-Turán
Suppose for an arbitrary group word
How did this question arise? There is a widely known theorem proved by P. Erdős and P. Turán that states:
A finite group
This theorem can be rephrased using aforementioned terminology as
K2-Think
The conjecture is not true for arbitrary group words ( w ). A counterexample can be constructed using a specific group word and analyzing the density of tuples satisfying the identity.
Consider the group word ( w(a,b,c) = [a,b]c ), where ( [a,b] = aba^{-1}b^{-1} ). The variety ( \mathfrak{U}_w ) consists of all groups ( G ) where ( [a,b]c = e ) for all ( a,b,c \in G ). This implies...
GPT-5
Rephrase. For a fixed group word w in n variables and a finite group G, write p_w(G) = |{(a1,…,an) in G^n : w(a1,…,an)=1}| / |G|^n. Your question asks whether for every word w there is a constant ε(w)>0 such that, for all finite groups G, p_w(G) > 1 − ε(w) implies that G satisfies the identity w≡1 (i.e. G lies in the variety U_w defined by w).
What is known.
- Commutator word. For w=[x,y] (abeli...
Claude Opus 4
This is a fascinating question about generalizing the Erdős-Turán theorem to arbitrary group words. Let me analyze this carefully.
The conjecture asks whether for every group word
Claude 3.7 Sonnet
Generalization of Erdős-Turán's 5/8 Theorem
This is an interesting question about generalizing the Erdős-Turán theorem to arbitrary group words. Let me analyze it carefully.
Understanding the Question
The question asks whether for any group word
o3 Pro
The problem you raised is exactly the problem of deciding whether a given word
w is a probabilistic identity.
For a word w in the free group F = 〈x1 , … , xn 〉 write
P G (w) = |{(a1 , … , an ) ∈ G n : w(a1 , … , an ) = 1}| ⁄ |G| n
(the probability that a random n–tuple in the finite group G satisfies w = 1). The question is:
(∗) Does every non-trivial word w admit ε(w) > 0 such that
...
o4 mini
First, let us restate the question in the language of “probabilistic identities.” Fix a word
w=w(x₁,…,xₙ)∈Fₙ,
and let 𝒰_w be the variety of (all) groups satisfying the identity w=1 . For a finite group G we set
p_G(w) = |{(g₁,…,gₙ)∈Gⁿ : w(g₁,…,gₙ)=1}| ÷ |G|ⁿ.
The conjecture is that for every word w there is an ε(w)>0 so that
G∈𝒰_w ⟺ p_G(w)>1−ε(w).
Equivalently o...
DeepSeek R1
The question is whether for any group word w, there's some epsilon(w) > 0 such that for any f...
o3
The problem you ask for is usually formulated as follows.
For a word w in n free generators put
p w (G)= |{(g1 ,…,gn )∈G n :w(g1 ,…,gn )=1}| /|G| n .
Question (P. M. Neumann, Kourovka Notebook, Problem 11.36).
Does every non–trivial word w admit a constant ε(w)>0 such that, for every finite group G,
p w (G)>1−ε(w) ⇒ w is an identity of G ?
Equivalently, is
sup {p w (G) : G f...
Gemini 2.5 Pro
This is an excellent and very natural question that gets to the heart of a field known as probabilistic group theory. The short answer to your question is no, the conjecture is not true for an arbitrary group word
The property you are asking about has a name. A variety of groups
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