19
Stack Exchange
votes

Coarse moduli spaces of stacks for which every atlas is a scheme

Posted on 11/6/2014
UQ ID:184
Science
MathOverflow
Original

Let be a smooth finite type separated DM-stack over given as the quotient of a smooth quasi-projective scheme by the action of a smooth (finite type separated) reductive group scheme . Since has finite inertia, the coarse space of exists as an algebraic space.

At atlas of is an étale morphism with an algebraic space.

I sm interested in the converse of the following statement:

Thm. If the coarse moduli space of is a scheme,then every atlas of is a scheme.

Proof. The map from an atlas to the coarse moduli space of is quasi-finite separated. Therefore is a scheme by Knutson Cor. II.6.16., p. 138 QED

So the converse would read as follows:

Q. Suppose that every atlas of is a scheme. Is the coarse moduli space of a scheme?

I expect the answer to be negative, but can't find a good example. Note that a counterexample can not be an algebraic space, as an algebraic space with the property that every atlas is a scheme is itself a scheme (the identity morphism being an atlas).

Edit: I have an application in mind of the above question, and in the context of my application the stack is even generically a scheme. Not sure if that helps...

Keywords & Tags
ag.algebraic-geometry
complex-geometry
stacks
algebraic-stacks
algebraic-spaces
Model Answers (9)
Submitted answers from various AI models
Unsolved
No reviews yet

K2-Think

Pending UQ Validation
Needs Human Verification
MBZUAI-IFM
Qwen2.5-32B
Sep 18, 2025, 01:50 PM

The converse statement holds. If every atlas ( U ) of a smooth finite type separated DM-stack ( X ) over ( \mathbb{C} ) (with finite inertia) is a scheme, then the coarse moduli space ( X^c ) must be a scheme.

Key Reasoning:

  1. Definition of Atlas and Coarse Space: An atlas of ( X ) is an étale surjective morphism ( U \to X ) where ( U ) is an algebraic space. The coarse mo...
0 model reviews
0 human reviews
No reviews yet

GPT-5

UQ Validated
Needs Human Verification
OpenAI
Sep 2, 2025, 06:56 AM

Yes. In fact you don’t need the hypothesis “every atlas is a scheme”; the existence of one étale atlas by a scheme already forces the coarse moduli space to be a scheme.

Here is a convenient way to see it.

  • Let π: X → Y be the coarse moduli space of a separated DM stack X with finite inertia (so Y is an algebraic space).
  • Pick an étale atlas p: U → X with U a scheme (such an atlas always exist...
0 model reviews
0 human reviews
No reviews yet

o3 Pro

Failed UQ Validation
Needs Human Verification
OpenAI
Aug 1, 2025, 12:00 AM

Yes – in the situation you describe the coarse moduli space is always a scheme, so the “converse” is automatically true. No counter–example can occur as long as

  1. the total space P is quasi-projective over ℂ, and
  2. the acting group G is a (connected) reductive algebraic group (or, more generally, a linearly reductive group scheme of finite type over ℂ).

Because of these two hypotheses ...

0 model reviews
0 human reviews
No reviews yet

o3

Failed UQ Validation
Needs Human Verification
OpenAI
Aug 1, 2025, 12:00 AM

Yes – under the hypotheses you stated the coarse moduli space is always a scheme, so the converse of your theorem holds vacuously. In fact the property that “every atlas is a scheme’’ is not needed: for a smooth quasi-projective scheme P endowed with an action of a (smooth, finite type, separated) reductive group G over ℂ the quotient sheaf P // G = P/G = X^c is a quasi-projective (...

0 model reviews
0 human reviews
No reviews yet

DeepSeek R1

Failed UQ Validation
Needs Human Verification
DeepSeek
deepseek-ai/DeepSeek-R1
Aug 1, 2025, 12:00 AM
<think> Okay, the user is asking about a specific scenario in algebraic geometry involving stacks and their coarse moduli spaces. They've presented a theorem stating that if the coarse moduli space is a scheme, then every atlas must be a scheme. Now they're asking about the converse: if every atlas is a scheme, must the coarse moduli space also be a scheme? They suspect the answer is no and want a...
0 model reviews
0 human reviews
No reviews yet

Claude 3.7 Sonnet

Failed UQ Validation
Needs Human Verification
Anthropic
Aug 1, 2025, 12:00 AM

Coarse Moduli Spaces of Stacks for Which Every Atlas is a Scheme

This is an interesting question in algebraic stack theory. Let me provide a detailed analysis.

The Question's Framework

We have a smooth, finite type, separated DM-stack over with finite inertia, where:

  • is a smooth quasi-projective scheme
  • is a smooth reductive group scheme

The author has ...

0 model reviews
0 human reviews
No reviews yet

Gemini 2.5 Pro

Failed UQ Validation
Needs Human Verification
Google
Aug 1, 2025, 12:00 AM

This is an excellent question. The answer is indeed negative, as you suspected. We can construct a counterexample using the idea that the "stackiness" of can be concentrated on a small locus, forcing any atlas (which must be an algebraic space) to live on the part of the stack that behaves like a scheme.

The Strategy

The core idea is to construct a Deligne-Mumford stack such that: 1....

0 model reviews
0 human reviews
No reviews yet

Claude Opus 4

Failed UQ Validation
Needs Human Verification
Anthropic
Aug 1, 2025, 12:00 AM

This is a very interesting question about the relationship between the nature of atlases of a stack and its coarse moduli space.

The answer to your question is negative - there exist stacks where every atlas is a scheme, but the coarse moduli space is not a scheme.

Here's a counterexample:

Counterexample: Consider the quotient stack where acts...

0 model reviews
0 human reviews
No reviews yet

o4 mini

Failed UQ Validation
Needs Human Verification
OpenAI
Aug 1, 2025, 12:00 AM

The short answer is: In fact nothing “mystical’’ is hiding here – already for any stack of the form

X = [P/G]  

with P smooth quasi–projective and G a reductive group over C (and with finite stabilizers) the Keel–Mori coarse moduli X^c is automatically a genuine scheme. In particular one does not need the extra hypothesis “every atlas of X is a scheme’’ in order to force X^c to be a schem...

0 model reviews
0 human reviews
Submit Your Model's Answer
Your submission will be validated by our LLM validator and then by human experts

You need to be logged in to submit an answer