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A Linear Order from AP Calculus

Posted on 8/27/2015
UQ ID:180
Science
MathOverflow
Original

In teaching my calculus students about limits and function domination, we ran into the class of functions

Suppose we say that weakly dominates , and write , if

We can then readily see that is a total order isomorphic to the lexicographic order on .

But we can get more complicated total orders with, say

which are isomorphic as total orders to the lexicographic orders on and

All of these complicated orders live inside what I'd call "the AP Calc linear order" defined as:

Missing \left or extra \right

where the refinement on is made so as to avoid problems with things like .

This seems to be a very complicated linear order, as it includes as a suborder things like

My question is the following: is there any combinatorial description or universal construction, i.e. as a colimit, of the isomorphism type of ?

Keywords & Tags
co.combinatorics
ct.category-theory
real-analysis
order-theory
linear-orders
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K2-Think

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Qwen2.5-32B
Sep 18, 2025, 01:50 PM

The "AP Calc linear order" ((\Omega, \preceq)) can be described as a colimit of a directed system of ordered sets, where each component corresponds to the hierarchy of polynomial-logarithmic functions (\Theta_n).

Each (\Theta_n) consists of functions of the form (x^{\alpha_0} (\ln x)^{\alpha_1} \cdots (\ln^{n-1} x)^{\alpha_{n-1}}) with (\vec{\alpha} \in \mathbb{R}^n), and its equivalen...

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GPT-5

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Sep 2, 2025, 06:56 AM

Short answer: as stated, Ω is not a linear order, and it is far too complicated to admit a nice “universal” combinatorial description. In fact, it already contains, as a suborder, the very complicated poset (P(ω), ⊆*) of subsets of the natural numbers ordered by inclusion modulo finite. So any hope for a simple colimit description in the spirit of your Θn- or Φ-examples cannot work without imposin...

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o3 Pro

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Aug 1, 2025, 12:00 AM

The relation you have written down is the usual “big-O’’ relation on germs of functions at :

f⪯g ⇔ lim sup_{x→∞}|f(x)/g(x)|<∞.

After passing to the equivalence relation
f∼g ⇔ f⪯g and g⪯f,
the elements of Ω are the positive germs modulo the relation “differ by a bounded factor’’ and the order is

[f]⪯[g] ⇔ f=O(g).

  1. (Ω,⪯) is not a linear order

Even afte...

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o4 mini

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Aug 1, 2025, 12:00 AM

One way to see that there really is a canonical “combinatorial” model for your big order is to observe that nothing mystical is hiding in the class of all continuous germs at infinity – as soon as one quotients out by “having the same size‐of‐growth,” one ends up with exactly the monomial group of the usual log–exp‐transseries. Equivalently one can build (\Omega) as the directed colimit of ...

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Claude 3.7 Sonnet

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Anthropic
Aug 1, 2025, 12:00 AM

Linear Orders in Asymptotic Comparison of Functions

The question explores a fascinating linear order structure derived from asymptotic function comparison. Let me address the request for a combinatorial description or universal construction of .

Understanding the Structure

The ordered set can be understood through the lens of transseries or **surrea...

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DeepSeek R1

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Aug 1, 2025, 12:00 AM
<think> I need to understand this question about a linear order from AP Calculus. The user is describing a hierarchy of functions based on their growth rates as x approaches infinity. Let me break this down step by step.

First, they define a set of functions Θ = {x^α (ln x)^β} for real numbers α and β. They say that g weakly dominates f, written f ⪯ g, if the limit as x approaches infinity of f(x...

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o3

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Aug 1, 2025, 12:00 AM

Write

    F := { all real–valued functions that are defined and continuous on
           some interval (λ , ∞) } ,
    B := { f∈F : f is bounded on (λ , ∞) for some λ } .  

Put an equivalence relation on F by

    f ≈ g  ⇔  f – g ∈ B ,  

and denote the ≈–class of f by [f].
Give the factor–set F/B the order

    [f] ≤ [g]  ⇔  (∃C∈ℝ)(  f(x) ≤ g(x)+C  for all large x )....
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Gemini 2.5 Pro

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Google
Aug 1, 2025, 12:00 AM

This is a fantastic question that touches on some deep and beautiful mathematics connecting analysis, algebra, and logic. The "AP Calc linear order" you've discovered is a gateway to the study of Hardy fields and transseries.

Let's break down the answer.

1. Correction: The Order is Not Linear on Ω

First, a crucial correction. The order as you've defined it on the *entire...

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Claude Opus 4

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Anthropic
Aug 1, 2025, 12:00 AM

This is a fascinating question about the structure of growth rates of functions, which connects analysis with order theory. Let me provide some insights into the combinatorial and categorical aspects of this linear order.

The Structure of

The linear order you've defined is indeed very rich. It contains all the "elementary functions" that appear in calcu...

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