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Is the equivariant cohomology an equivariant cohomology?

Posted on 6/20/2011
UQ ID:136
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Suppose a finite group acts piecewise linearly on a polyhedron . Then there are two kinds of equivariant cohomology (or homology).

With coefficients in a -module . A reference is K. Brown's "Cohomology of groups". Namely, , where is the simplicial chain complex of a suitable invariant triangulation of . Note that . Generalized cohomology (including stable cohomotopy) of with coefficients in a module can be defined via generalized cohomology of with local coefficients, which in turn is defined in the last chapter of the Buoncristiano-Rourke-Sanderson book.

Representation-graded. A reference is "Equivariant homotopy and cohomology theory" by J. P. May et al. (but to simplify matters, I'm thinking of trivial coefficients, as in Segal and Kosniowski rather than coefficients in a Mackey functor). Instead of defining let me only say that there is a Hurewicz homomorphism , and the equivariant stable cohomotopy can be defined as the equivariant homotopy set , where is a sufficiently large (with respect to the partial order by inclusion) finite-dimensional -submodule of , and the "representation sphere" is the one-point compactification of (viewed as a Euclidean space with an action of ).

What relations are there between these two kinds of (e.g. ordinary) equivariant cohomology? More specifically,

is cohomology with coefficients in a -module a special case of representation-graded cohomology?

A related (equivalent?) question is whether cohomology with coefficients in a (nontrivial!) module is representable in some reasonable sense.

For instance, by reducing both sides to non-equivariant cohomology, I know that , where acts freely on , (basepoint), is the augmentation ideal of (so is if is even and if is odd) and is the augmentation ideal of (so is with the antipodal involution). Something of this kind can also be done for stable cohomotopy. However this all depends on a twisted Thom isomorphism which I don't know for more general modules.

Keywords & Tags
at.algebraic-topology
equivariant-homotopy
equivariant
group-cohomology
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K2-Think

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Qwen2.5-32B
Sep 18, 2025, 01:50 PM

The relationship between cohomology with coefficients in a ℤG-module and RO(G)-graded (genuine) equivariant cohomology is nuanced, and they are not generally special cases of one another. Here's a structured breakdown:

1. Definitions and Grading

  • ℤG-module coefficient cohomology (Borel-equivariant): This is a ℤ-graded theory, denoted ( H^\ast_G(X; M) ), defined using the equivariant ch...
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GPT-5

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Sep 2, 2025, 06:56 AM

Short answer: No. Cohomology with coefficients in a ZG–module (i.e. Borel-equivariant cohomology with local coefficients pulled back from BG) is not a special case of “genuine,” RO(G)-graded equivariant cohomology. It is a different flavor of equivariant theory. It is representable, but not by an RO(G)-graded Eilenberg–MacLane G-spectrum of the sort used in May’s book; rather it is represented eit...

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o3 Pro

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Aug 1, 2025, 12:00 AM

No – the two theories live in different “equivariant worlds’’ and only coincide after one forces the action to be free (or, more generally, after smashing with EG₊). Nevertheless the groups H⁎_{G}(X;M) that Brown defines are representable, and the relation with RO(G)-graded ordinary (Bredon) cohomology can be described very explicitly.

------------------------------------------------------------...

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o4 mini

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Aug 1, 2025, 12:00 AM

There are in fact two different “equivariant‐cohomology” machines hiding behind your two bullets, and one only becomes the other in very special cases. Let me try to disentangle them and then explain exactly how and when local‐coefficient cohomology sits inside an RO(G)–theory.

  1. Borel cohomology with –coefficients.
    By definition [ H_G^(X;M);=;H^!\bigl(\Hom_{\Z G}(C_*(X)...
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o3

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Aug 1, 2025, 12:00 AM

Short answer

For an arbitrary left ℤG–module M the “Borel–type” groups
HG(X;M)=H(EG×G X;𝔐)
(where 𝔐 is the local coefficient system determined by M) form only a naive equivariant cohomology theory: they are indexed by the ordinary integers and are representable by a naive G–spectrum EG M:=F(EG+,HM) .
(Here HM is the nonequivariant Eilenberg–Mac Lane spectrum of M and the G–...

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Gemini 2.5 Pro

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Aug 1, 2025, 12:00 AM

Excellent question. It gets to the heart of the distinction between two fundamental approaches to equivariant cohomology, often called the "Borel" and "genuine" (or "homotopical") theories.

The short answer to your main question is:

Yes, ordinary equivariant cohomology with coefficients in a -module is a special case of representation-graded ("genuine") equivariant cohomology....

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DeepSeek R1

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Aug 1, 2025, 12:00 AM
<think> Okay, the user is asking about the relationship between two different types of equivariant cohomology. Let me start by understanding the question details. The user mentions two kinds: one with coefficients in a ℤG-module, like in Brown's book, and the other being representation-graded, as in May's work. The main question is whether the first is a special case of the second.

First, I need ...

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Claude 3.7 Sonnet

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Anthropic
Aug 1, 2025, 12:00 AM

Is Equivariant Cohomology with Coefficients in a Module a Special Case of Representation-Graded Equivariant Cohomology?

This question asks about the relationship between two notions of equivariant cohomology: one with coefficients in a -module and the other graded by representations.

The Relationship Between the Two Notions

The short answer is: **in general, cohomology with co...

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Claude Opus 4

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Anthropic
Aug 1, 2025, 12:00 AM

This is a deep question about the relationship between two different approaches to equivariant cohomology. Let me clarify the relationship and address your specific question.

The Two Approaches

  1. Bredon cohomology (your first bullet): This is cohomology with coefficients in a -module, defined as .

  2. RO(G)-graded cohomology (y...

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